document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=680793>Question 680793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 15.6% copper to make jewelry. How many ounces of an alloy that is 14% copper must be mixed with an alloy that is 16% copper to form 100 ounces of the desired alloy?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422460 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	percent	----------------			quantity									<BR>\n" );
document.write( "Metal alloy I	14	----------------			x	ounces								<BR>\n" );
document.write( "Metal alloy II	16	------	100	-	x	ounces								<BR>\n" );
document.write( "Mixture	16	----------------	100											<BR>\n" );
document.write( "														<BR>\n" );
document.write( "14x+16(100-x)=15.6*100		<BR>\n" );
document.write( "1400x+1600(100-	x)=156000				<BR>\n" );
document.write( "1400x+160000-1600x=156000				<BR>\n" );
document.write( "1400x-1600x=	156000	-160000				<BR>\n" );
document.write( "-200	x			=	-4000									<BR>\n" );
document.write( "/	-200													<BR>\n" );
document.write( "x=20ounces	14.00%		Metal alloy I		<BR>\n" );
document.write( "80	ounces			16.00%		Metal alloy II		<BR>\n" );
document.write( "														<BR>\n" );
document.write( "m.ananth@hotmail.ca														<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );