document.write( "Question 680763: Can anyone help me solve this problem for Logic? (P → Q) ↔ (星 ∨ Q)?
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document.write( "There are no premises given. Just that which is the goal id really appreciate it. \n" );
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Algebra.Com's Answer #422459 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "We'll do each case separately then we'll\r\n" ); document.write( "put the four cases into a truth table:\r\n" ); document.write( "\r\n" ); document.write( "(P → Q) ↔ (星 ∨ Q)\r\n" ); document.write( "\r\n" ); document.write( "Let \"T\" mean \"true\" and let \"F\" be \"false:\r\n" ); document.write( "\r\n" ); document.write( "Case 1: P is true and Q is true:\r\n" ); document.write( "\r\n" ); document.write( "(P → Q) ↔ (星 ∨ Q)\r\n" ); document.write( "(T → T) ↔ (曷 ∨ T)\r\n" ); document.write( " T ↔ ( F ∨ T)\r\n" ); document.write( " T ↔ T\r\n" ); document.write( " T\r\n" ); document.write( "\r\n" ); document.write( "Case 2: P is true and Q is false:\r\n" ); document.write( "\r\n" ); document.write( "(P → Q) ↔ (星 ∨ Q)\r\n" ); document.write( "(T → F) ↔ (曷 ∨ F)\r\n" ); document.write( " F ↔ ( F ∨ F)\r\n" ); document.write( " F ↔ F\r\n" ); document.write( " T\r\n" ); document.write( "\r\n" ); document.write( "Case 3: P is false and Q is true:\r\n" ); document.write( "\r\n" ); document.write( "(P → Q) ↔ (星 ∨ Q)\r\n" ); document.write( "(F → T) ↔ (政 ∨ T)\r\n" ); document.write( " T ↔ ( T ∨ T)\r\n" ); document.write( " T ↔ T\r\n" ); document.write( " T \r\n" ); document.write( "\r\n" ); document.write( "Case 4: P is false and Q is false:\r\n" ); document.write( "\r\n" ); document.write( "(P → Q) ↔ (星 ∨ Q)\r\n" ); document.write( "(F → F) ↔ (政 ∨ F)\r\n" ); document.write( " T ↔ ( T ∨ F)\r\n" ); document.write( " T ↔ T\r\n" ); document.write( " T \r\n" ); document.write( "\r\n" ); document.write( "It is true in all four cases, so it is a tautology.\r\n" ); document.write( "\r\n" ); document.write( "Or you can do it as a truth table which is equivalent to\r\n" ); document.write( "the four cases above:\r\n" ); document.write( "\r\n" ); document.write( " | P | Q | 星 | P → Q | 星 ∨ Q | (P → Q) ↔ (星 ∨ Q |\r\n" ); document.write( "case 1: | T | T | F | T | T | T | \r\n" ); document.write( "case 2: | T | F | F | F | F | T | \r\n" ); document.write( "case 3: | F | T | T | T | T | T | \r\n" ); document.write( "case 4: | F | F | T | T | T | T | \r\n" ); document.write( "\r\n" ); document.write( "Since the last column came out all trues, the original statement\r\n" ); document.write( "is a tautology.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |