document.write( "Question 680789: use the quadrtic formula for:
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\n" ); document.write( "4x^2+x-3=0
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Algebra.Com's Answer #422458 by mananth(16946)\"\" \"About 
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4x^2+x-3=0
\n" ); document.write( "compare with ax^2+bx+c=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= 4 b= 1 c= -3
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\n" ); document.write( "b^2-4ac= 1 - -48
\n" ); document.write( "b^2-4ac= 49 \"sqrt%28%0949%09%29\"= 7
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -1 + 7 )/ 8
\n" ); document.write( "x1= 0.75
\n" ); document.write( "x2=( -1 -7 ) / 8
\n" ); document.write( "x2= -1
\n" ); document.write( "The roots are 0.75,-1
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