document.write( "Question 680782: A father is six times as old
\n" ); document.write( "as the son. Four years ago
\n" ); document.write( "the father was ten times
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Algebra.Com's Answer #422456 by mananth(16946)\"\" \"About 
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son's age =x
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\n" ); document.write( "\n" ); document.write( "4 years ago
\n" ); document.write( "son's age = x-4
\n" ); document.write( "father's age =6x-4\r
\n" ); document.write( "\n" ); document.write( "conditon
\n" ); document.write( "6x-4=10(x-4)
\n" ); document.write( "6x-4=10x-40
\n" ); document.write( "6x-10x=-40+4
\n" ); document.write( "-4x=-36
\n" ); document.write( "/-4
\n" ); document.write( "x=9\r
\n" ); document.write( "\n" ); document.write( "son's age = 9 years
\n" ); document.write( "father's age = 6x= 54\r
\n" ); document.write( "\n" ); document.write( "son's age 3 years later --> x+3= 9+3=12
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