document.write( "Question 680782: A father is six times as old
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document.write( "as the son. Four years ago
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document.write( "the father was ten times
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document.write( "as old as his son.
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document.write( "Find the
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document.write( "1. son's age
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document.write( "2. Father's age
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document.write( "3. Son's age in 3yrs times.
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Algebra.Com's Answer #422456 by mananth(16946)![]() ![]() You can put this solution on YOUR website! son's age =x \n" ); document.write( "father's age =6x\r \n" ); document.write( "\n" ); document.write( "4 years ago \n" ); document.write( "son's age = x-4 \n" ); document.write( "father's age =6x-4\r \n" ); document.write( "\n" ); document.write( "conditon \n" ); document.write( "6x-4=10(x-4) \n" ); document.write( "6x-4=10x-40 \n" ); document.write( "6x-10x=-40+4 \n" ); document.write( "-4x=-36 \n" ); document.write( "/-4 \n" ); document.write( "x=9\r \n" ); document.write( "\n" ); document.write( "son's age = 9 years \n" ); document.write( "father's age = 6x= 54\r \n" ); document.write( "\n" ); document.write( "son's age 3 years later --> x+3= 9+3=12 \n" ); document.write( " \n" ); document.write( " |