document.write( "Question 680571: y+3/y-3=y-4/y-5+1
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Algebra.Com's Answer #422390 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
y+3/y-3=y-4/y-5+1
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\n" ); document.write( "(y+3)/(y-3) = (y-4)/(y-5) + 1
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\n" ); document.write( "Multiply thru by (y-3)(y-5) to get:
\n" ); document.write( "(y+3)(y-5) = (y-4)(y-3) + (y-3)(y-5)
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\n" ); document.write( "y^2 - 2y - 15 = y^2-7y+12 + y^2-8y+15
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\n" ); document.write( "y^2 -2y-15 = 2y^2-15y + 27
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\n" ); document.write( "y^2 - 13y +42 = 0
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\n" ); document.write( "Factor:(y-6)(y-7) = 0
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\n" ); document.write( "y = 6 or y = 7
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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