document.write( "Question 680219: After 6 years the ratio of age of X and Y will be 5:6. Before 6 years it was 3:4. Find the age of younger one. \n" ); document.write( "
Algebra.Com's Answer #422362 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! \"After 6 years the ratio of age of X and Y will be 5:6.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "6(x+6) = 5(y+6) \n" ); document.write( "6x + 36 = 5y + 30 \n" ); document.write( "6x - 5y = 30 - 36 \n" ); document.write( "6x - 5y = -6 \n" ); document.write( ": \n" ); document.write( "\" Before 6 years it was 3:4.\" \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "4(x-6) = 3(y-6) \n" ); document.write( "4x - 24 = 3y - 18 \n" ); document.write( "4x - 3y = -18 + 24 \n" ); document.write( "4x - 3y = 6 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by -3, the 2nd equation by 5 \n" ); document.write( "-18x + 15y = 18 \n" ); document.write( " 20x - 15y = 30 \n" ); document.write( "-----------------adding eliminates y, findx \n" ); document.write( "2x = 48 \n" ); document.write( "x = 24 yrs old \n" ); document.write( ": \n" ); document.write( "find y \n" ); document.write( "4x - 3y = 6 \n" ); document.write( "4(24) - 3y = 6 \n" ); document.write( "96 - 3y = 6 \n" ); document.write( "-3y = 6 - 96 \n" ); document.write( "-3y = -90 \n" ); document.write( "y = -90/-3 \n" ); document.write( "y = 30 yrs old \n" ); document.write( ": \n" ); document.write( "Find the age of younger one. 24 yrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st statement; \n" ); document.write( "\"After 6 years the ratio of age of X and Y will be 5:6.\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |