document.write( "Question 680462: Jennifer leaves her house going 25 mph. Her mom leaves 20 minutes later, going 90 mph. When will Mom catch up with Jennifer? \n" ); document.write( "
Algebra.Com's Answer #422342 by stanbon(75887)\"\" \"About 
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Jennifer leaves her house going 25 mph. Her mom leaves 20 minutes later, going 90 mph. When will Mom catch up with Jennifer?
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\n" ); document.write( "Jennifer DATA:
\n" ); document.write( "rate = 25 mph ; time = x hrs ; distance = 25x miles
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\n" ); document.write( "Mom DATA:
\n" ); document.write( "rate = 90 mph ; time = (x-(1/3)) hrs ; distance = 90x-30 miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "25x = 90x-30
\n" ); document.write( "65x = 30
\n" ); document.write( "x = 6/13 hrs = (6/13)*60 = 27.69 = 27 min 42 seconds
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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