document.write( "Question 680439: how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution \n" ); document.write( "
Algebra.Com's Answer #422329 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution
\n" ); document.write( "-------
\n" ); document.write( "Using 2 equation:
\n" ); document.write( "Quantity Eq:: x + 60 = y
\n" ); document.write( "Alcohol Eq:::0.40x + 0.70*60 = 0.50y
\n" ); document.write( "------------
\n" ); document.write( "Multiply thru Quantity Eq by 40
\n" ); document.write( "Multiply thru Alcohol Eq by 100
\n" ); document.write( "------
\n" ); document.write( "40x + 40*60 = 40y
\n" ); document.write( "40x + 70*60 = 50y
\n" ); document.write( "-----
\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "30*60 = 10y
\n" ); document.write( "y = 180 liters
\n" ); document.write( "------
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + 60 = y
\n" ); document.write( "x + 60 = 180
\n" ); document.write( "x = 120 liters (amt. of 40% solution needed)\r
\n" ); document.write( "\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );