document.write( "Question 680439: how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution \n" ); document.write( "
Algebra.Com's Answer #422329 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution \n" ); document.write( "------- \n" ); document.write( "Using 2 equation: \n" ); document.write( "Quantity Eq:: x + 60 = y \n" ); document.write( "Alcohol Eq:::0.40x + 0.70*60 = 0.50y \n" ); document.write( "------------ \n" ); document.write( "Multiply thru Quantity Eq by 40 \n" ); document.write( "Multiply thru Alcohol Eq by 100 \n" ); document.write( "------ \n" ); document.write( "40x + 40*60 = 40y \n" ); document.write( "40x + 70*60 = 50y \n" ); document.write( "----- \n" ); document.write( "Subtract and solve for \"y\": \n" ); document.write( "30*60 = 10y \n" ); document.write( "y = 180 liters \n" ); document.write( "------ \n" ); document.write( "Solve for \"x\": \n" ); document.write( "x + 60 = y \n" ); document.write( "x + 60 = 180 \n" ); document.write( "x = 120 liters (amt. of 40% solution needed)\r \n" ); document.write( "\n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |