document.write( "Question 680309: Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function.
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document.write( "sq rt.y=3-4x
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document.write( "sq rt y^-3=-4x
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document.write( "x=(sq rt y^-3)/-4
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document.write( "f^-1(x)=sq rt y^-3/-4 and it is not a function. Thanks \n" );
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Algebra.Com's Answer #422284 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function. \n" ); document.write( "sq rt.y=3-4x \n" ); document.write( "sq rt y^-3=-4x ****** The ^ is unnecessary and confusing **** \n" ); document.write( "x=(sq rt y^-3)/-4 \n" ); document.write( "f^-1(x)=sq rt y^-3/-4 and it is not a function. Thanks \n" ); document.write( "------------------- \n" ); document.write( "f(x)=(3-4x)^2 \n" ); document.write( "y = (3-4x)^2 \n" ); document.write( "--> x = (3-4y)^2 \n" ); document.write( "3-4y = sqrt(x) \n" ); document.write( "y = (3 - sqrt(x))/4 Same as your answer.\r \n" ); document.write( "\n" ); document.write( "Not a function. \n" ); document.write( " \n" ); document.write( " |