document.write( "Question 680004: the sum of the perimeters of two square lots is 140 meters while the sum of their areas is 625 square meters. what are the measures of the side of the squares? i also need solutions \n" ); document.write( "
Algebra.Com's Answer #422232 by ankor@dixie-net.com(22740)\"\" \"About 
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the sum of the perimeters of two square lots is 140 meters
\n" ); document.write( " while the sum of their areas is 625 square meters.
\n" ); document.write( " what are the measures of the side of the squares?
\n" ); document.write( ":
\n" ); document.write( "Let x = the side of one of the square lots
\n" ); document.write( "Let y = the side of the other
\n" ); document.write( "Perimeter sum
\n" ); document.write( "4x + 4y = 140
\n" ); document.write( "simplify, divide by 4
\n" ); document.write( "x + y = 35
\n" ); document.write( "y = (35-x)
\n" ); document.write( ":
\n" ); document.write( "The area sum
\n" ); document.write( "x^2 + y^2 = 625
\n" ); document.write( "replace y
\n" ); document.write( "x^2 + (35-x)^2 = 625
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 1225 - 70x + x^2 = 625
\n" ); document.write( "2x^2 - 70x + 1225 - 625 = 0
\n" ); document.write( "2x^2 - 70x + 600 = 0
\n" ); document.write( "Simplify divide by 2
\n" ); document.write( "x^2 - 35x + 300 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-20)(2-15) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 20, then y = 15
\n" ); document.write( "x = 15, then y = 20
\n" ); document.write( ":
\n" ); document.write( "The sides of the two squares are 15 and 20
\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( "4(20) + 4(15) = 140
\n" ); document.write( "20^2 + 15^2 = 625 \n" ); document.write( "
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