document.write( "Question 679914: need help please
\n" ); document.write( "20-z/3=z/2
\n" ); document.write( "am I supposed to multiply both sides by 20?
\n" ); document.write( "multiply the 3 and the 2 by 20?
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Algebra.Com's Answer #422184 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"20-z%2F3=z%2F2\"...here you have whole number \"20\" and fractions \"-z%2F3\" and \"z%2F2\"; so, you need to get a rid of fractions and have all whole numbers
\n" ); document.write( "in order to do that, you need to multiply both sides with LCD for \"2\" and \"3\" which is \"6\"\r
\n" ); document.write( "\n" ); document.write( "\"20%2A6-%28z%2F3%296=%28z%2F2%296\"\r
\n" ); document.write( "\n" ); document.write( "\"120-%28z%2Fcross%283%29%29cross%286%292=%28z%2Fcross%282%29%29cross%286%293\"\r
\n" ); document.write( "\n" ); document.write( "\"120-2z=3z\"\r
\n" ); document.write( "\n" ); document.write( "\"120=3z%2B2z\"\r
\n" ); document.write( "\n" ); document.write( "\"120=5z\"\r
\n" ); document.write( "\n" ); document.write( "\"120%2F5=z\"\r
\n" ); document.write( "\n" ); document.write( "\"24=z\"\r
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