document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679975>Question 679975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in this percentage problem. Thank you. \r<BR>\n" );
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document.write( "How much pure acid should be mixed with 6 gallons of a 50 % acid solution in order to get an 80 % acid solution?\r<BR>\n" );
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document.write( "A) 15 gal<BR>\n" );
document.write( "B) 3 gal<BR>\n" );
document.write( "C) 9 gal<BR>\n" );
document.write( "D) 24 gal  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422169 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much pure acid should be mixed with 6 gallons of a 50 % acid solution in order to get an 80 % acid solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.50*6 + 1.00x = 0.80(6+x)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "50*6 + 100x = 80*6 + 80x<BR>\n" );
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document.write( "20x = 30*6<BR>\n" );
document.write( "x = 9 gallons (amt. of pure acid to be added)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "A) 15 gal<BR>\n" );
document.write( "B) 3 gal<BR>\n" );
document.write( "C) 9 gal<BR>\n" );
document.write( "D) 24 gal <BR>\n" );
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