document.write( "Question 679898: An investor has $7000 to invest in two accounts. The first account earns 6% annual simple interest, and the second account earns 10% annual simple interest. How much money should be invested in each account so that the annual simple interest earned is $900? (If not possible, enter IMPOSSIBLE.)
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Algebra.Com's Answer #422120 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = amount invested at 6%
\n" ); document.write( "Let $\"+b+\"$ = amount invested at 10%
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+a+%2B+b+=+7000+\"$
\n" ); document.write( "(2) $\"+.06a+%2B+.1b+=+900+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "(2) $\"+6a+%2B+10b+=+90000+\"$
\n" ); document.write( "Multiply both sides of (1) by $\"+6+\"$
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) $\"+6a+%2B+10b+=+90000+\"$
\n" ); document.write( "(1) $\"+-6a+-+6b+=+-42000+\"$
\n" ); document.write( " $\"+4b+=+48000+\"$
\n" ); document.write( " $\"+b+=+12000+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+a+%2B+12000+=+7000+\"$
\n" ); document.write( "(1) $\"+a+=+-5000+\"$
\n" ); document.write( "It is impossible.
\n" ); document.write( "Even if the investor got 10% from both accounts,
\n" ); document.write( "the interest would only be $700\r
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