document.write( "Question 7668: Can you please show me how to work this problem out?\r
\n" ); document.write( "\n" ); document.write( "2a+b=14
\n" ); document.write( "3a+b+4\r
\n" ); document.write( "\n" ); document.write( "(this is one problem.)
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Algebra.Com's Answer #4221 by bonster(299)\"\" \"About 
You can put this solution on YOUR website!
2a+b=14
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\n" ); document.write( "\n" ); document.write( "Multiply one set with -1 to cancel out b:
\n" ); document.write( "-(2a+b=14)
\n" ); document.write( "3a+b+4 \r
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\n" ); document.write( "\n" ); document.write( "-2a-b=-14
\n" ); document.write( "3a+b+4\r
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\n" ); document.write( "\n" ); document.write( "add the two verticaly
\n" ); document.write( "a=-10\r
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\n" ); document.write( "\n" ); document.write( "To find b, multiply the first set by 3 and the second by -2:
\n" ); document.write( "2a+b=14
\n" ); document.write( "3a+b+4 \r
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\n" ); document.write( "\n" ); document.write( "3(2a+b=14)
\n" ); document.write( "-2(3a+b=4)\r
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\n" ); document.write( "\n" ); document.write( "6a+3b=42
\n" ); document.write( "-6a-2b=-8
\n" ); document.write( "b=34\r
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\n" ); document.write( "\n" ); document.write( "a=-10
\n" ); document.write( "b=34
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