document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679718>Question 679718</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Three times a number decreased by two, is equal to twice the same<BR>\n" );
document.write( "number increased by seven.\r<BR>\n" );
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document.write( "Ive made it into 3x-2=2x+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422040 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Now just do some basic algebra<BR>\n" );
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document.write( "3x - 2 = 2x + 7<BR>\n" );
document.write( "add 2 to each side<BR>\n" );
document.write( "3x = 2x + 7 + 2<BR>\n" );
document.write( "3x = 2x + 9<BR>\n" );
document.write( "subtract 2x from both sides<BR>\n" );
document.write( "3x - 2x = 9<BR>\n" );
document.write( "x = 9<BR>\n" );
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document.write( "Check this; substitute 9 for x in the original equation, see that equality reigns! </SPAN>\n" );
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