document.write( "Question 679717: in triangle ABC, angle C is three times as large as angle A. Angle B measures 5 degrees less than angle A. Find the measures of each angle \n" ); document.write( "
Algebra.Com's Answer #422036 by pmatei(79)\"\" \"About 
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In any triangle: \r
\n" ); document.write( "\n" ); document.write( "\"angleA+%2B+angleB+%2B+angle+C+=+180\"\r
\n" ); document.write( "\n" ); document.write( "The problem states:\r
\n" ); document.write( "\n" ); document.write( "\"angle+C+=+3%2Aangle+A\"\r
\n" ); document.write( "\n" ); document.write( "\"angle+B+=+angleA+-+5\"\r
\n" ); document.write( "\n" ); document.write( "Substitute angleB and angleC in the first equation with the right side of the second and third equations:\r
\n" ); document.write( "\n" ); document.write( "\"angleA+%2B+%28angleA+-+5%29+%2B+%283%2AangleA%29+=+180\"\r
\n" ); document.write( "\n" ); document.write( "\"5%2AangleA+-+5+=+180\"\r
\n" ); document.write( "\n" ); document.write( "Add 5 to both sides of the equation:\r
\n" ); document.write( "\n" ); document.write( "\"5%2AangleA+=+185\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 5:\r
\n" ); document.write( "\n" ); document.write( "\"angleA+=+37\"\r
\n" ); document.write( "\n" ); document.write( "\"angleB+=+angleA+-+5+=+37-5=32\"\r
\n" ); document.write( "\n" ); document.write( "\"angleC+=+3%2AangleA+=+3%2A37+=+111\"\r
\n" ); document.write( "\n" ); document.write( "Solution check:\r
\n" ); document.write( "\n" ); document.write( "\"37+%2B+32+%2B+111+=+180\"
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