document.write( "Question 679707: could you please show me how to slove these to find x. \r
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document.write( "log(x+1)+ log(x-1)=log24\r
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document.write( "2log(base of 4)x-log(base of 4)(x+3)=1 \n" );
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Algebra.Com's Answer #422034 by pmatei(79) ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You cannot have negative numbers under logarithm, so the only solution is:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because of the (x+3) in the denominator of the fractions, x cannot be -3 (we cannot divide by zero).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because of the \n" ); document.write( "\n" ); document.write( "Final solution |