document.write( "Question 679707: could you please show me how to slove these to find x. \r
\n" ); document.write( "\n" ); document.write( "log(x+1)+ log(x-1)=log24\r
\n" ); document.write( "\n" ); document.write( "2log(base of 4)x-log(base of 4)(x+3)=1
\n" ); document.write( "

Algebra.Com's Answer #422034 by pmatei(79)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2B1%29+%2B+log%28x-1%29+=+log24\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x%2B1%29%28x-1%29%29+=+log24\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%28x-1%29+=+24\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+1+=+24\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+25\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+5\" or \"x=-5\"\r
\n" ); document.write( "\n" ); document.write( "You cannot have negative numbers under logarithm, so the only solution is:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2log%284%2Cx%29+-+log%284%2C%28x%2B3%29%29+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2Cx%5E2%29+-+log%284%2C%28x%2B3%29%29+=+log%284%2C4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2C%28x%5E2%2F%28x%2B3%29%29%29+=+log%284%2C4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F%28x%2B3%29+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Because of the (x+3) in the denominator of the fractions, x cannot be -3 (we cannot divide by zero).\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+4%28x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+4x+%2B12\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+4x+-+12+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%28x%2B2%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"x-6+=+0\" or \"x%2B2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x=6\" or \"x=-2\"\r
\n" ); document.write( "\n" ); document.write( "Because of the \"log%284%2Cx%29\", we cannot accept the \"x=-2\" solution - no negative numbers under logarithm.\r
\n" ); document.write( "\n" ); document.write( "Final solution \"x=6\".
\n" ); document.write( "
\n" );