document.write( "Question 679662: \r
\n" ); document.write( "\n" ); document.write( "How many gallons of 10% alcohol solution and 75% alcohol solution must be mixed to get 25 gallons of 50% alcohol solution?
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Algebra.Com's Answer #422027 by checkley79(3341)\"\" \"About 
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.10X+.75(25-X)=.50*25
\n" ); document.write( ".10X+18.75-.75X=12.50
\n" ); document.write( "-.65X=12.50-18.75
\n" ); document.write( "-.65X=-6.25
\n" ); document.write( "X=-6.25/-.65
\n" ); document.write( "X=9.6154 GALLONS OF 10% ALCOHOL IS USED.
\n" ); document.write( ".10*9.6154+.75(25-9.615=.50*25
\n" ); document.write( ".96154+.75*15.385=12.50
\n" ); document.write( ".96154+11.538=12.50
\n" ); document.write( "12.50=12.50
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