document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679700>Question 679700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> joe jogs 2.5 slower than kelly jogs. in the time that it takes joe to jog 30 miles, kathy can jog 40 miles. find the jogging speed of each person. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #422021 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=422021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> joe jogs 2.5 slower than kelly jogs. in the time that it takes joe to jog 30 miles, kathy can jog 40 miles. find the jogging speed of each person.<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "2.5 what?<BR>\n" );
document.write( "If it's 2.5 mi/hr,<BR>\n" );
document.write( "r = Joe's rate<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "30/r = 40/(r+2.5)<BR>\n" );
document.write( "30r + 75 = 40r<BR>\n" );
document.write( "r = 7.5 mi/hr<BR>\n" );
document.write( "Kelly's rate = 10 mi/hr<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );