document.write( "Question 679678: twice the first of three consecutive even integers minus the third equals 36. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #422011 by stanbon(75887) $\"\"$ $\"About$

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twice the first of three consecutive even integers minus the third equals 36. Find the three integers.
\n" ); document.write( "1st: 2x-2
\n" ); document.write( "2nd: 2x
\n" ); document.write( "3rd: 2x+2
\n" ); document.write( "-------
\n" ); document.write( "Equation:
\n" ); document.write( "2(2x-2)-(2x+2)= 36
\n" ); document.write( "4x-4-2x-2 = 36
\n" ); document.write( "2x = 42
\n" ); document.write( "x = 21
\n" ); document.write( "-------
\n" ); document.write( "1st: 2*21-2 = 40
\n" ); document.write( "2nd: 42
\n" ); document.write( "3rd: 44
\n" ); document.write( "-----------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============== \n" ); document.write( "

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