document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679660>Question 679660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angle a is complementary to angle c. if angle a is equal to 2x-10 and angle c is equal to 4x+40, find the measurement angle of a, the measurement angle of c, and the measurement angle of b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421999 by </B><A HREF=/tutors/aboutme.mpl?userid=RichardMathsTutor><B>RichardMathsTutor(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RichardMathsTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If angle a is complimentary to angle c then angle a and angle c add up to 90 degrees.\r<BR>\n" );
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document.write( "So angle a + angle c = 90<BR>\n" );
document.write( "If angle a = 2x-10 and angle c = 4x+40<BR>\n" );
document.write( "Then 2x-10+4x+40 = 90<BR>\n" );
document.write( "Simplifying LHS gives 6x+30 = 90, and thus 6x = 60 or x = 10\r<BR>\n" );
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document.write( "Substituting this value of x into 2x-10 and 4x+40 gives:\r<BR>\n" );
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document.write( "angle a = 2(10)-10 = 10, angle c = 4(10)+40 = 80\r<BR>\n" );
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document.write( "To check; angle a + angle c = 10+80 = 90, this is complimentary.\r<BR>\n" );
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document.write( "More information is needed regarding angle b. </SPAN>\n" );
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