document.write( "Question 679635: Chance paddled a canoe 10 miles upstream in a river that has a current of 4 mph. He then turned around and paddled downstream until he reached his original starting place. If the entire trip took him 7 hours, how fast would Chance paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #421997 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+s+\" = the speed of the boat in still water
\n" ); document.write( "\"+s+%2B+4+\" = speed of canoe going downstream
\n" ); document.write( "\"+s+-+4+\" = speed of canoe going upstream
\n" ); document.write( "Let \"+t+\" = time to go upstream
\n" ); document.write( "\"+7+-+t+\" = time to go downstream
\n" ); document.write( "------------------
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(1) \"+10+=+%28+s+-+4+%29%2At+\"
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(2) \"+10+=+%28+s+%2B+4+%29%2A%28+7+-+t+%29+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "(1) \"+t+=+10+%2F+%28+s+-+4+%29+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+10+=+7s+%2B+28+-+s%2At+-+4t+\"
\n" ); document.write( "(2) \"+10+=+7s+%2B+28+-+t%2A%28+s+%2B+4+%29+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+10+=+7s+%2B+28+-+%28+10+%2F+%28+s+-+4+%29+%29%2A%28+s+%2B+4+%29+\"
\n" ); document.write( "(2) \"+7s+%2B+18+=+++%28+10+%2F+%28+s+-+4+%29+%29%2A%28+s+%2B+4+%29+\"
\n" ); document.write( "Multiply both sides by \"+s+-+4+\"
\n" ); document.write( "(2) \"+%28+s+-+4+%29%2A%28+7s+%2B+18+%29+=+10s+%2B+40+\"
\n" ); document.write( "(2) \"+7s%5E2+-+28s+%2B+18s+-+72+=+10s+%2B+40+\"
\n" ); document.write( "(2) \"+7s%5E2+-+20s+-112+=+0+\"
\n" ); document.write( "Use quadratic formula
\n" ); document.write( "\"+s+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+7+\"
\n" ); document.write( "\"+b+=+-20+\"
\n" ); document.write( "\"+c+=+-112+\"
\n" ); document.write( "\"+s+=+%28+-%28-20%29+%2B-+sqrt%28+%28-20%29%5E2+-+4%2A7%2A%28-112%29+%29%29+%2F+%282%2A7%29+\"
\n" ); document.write( "\"+s+=+%28+20+%2B-+sqrt%28+400+%2B+3136+%29%29+%2F+14+\"
\n" ); document.write( "\"+s+=+%28+20+%2B+sqrt%28+3536+%29%29+%2F+14+\"
\n" ); document.write( "\"+s+=+%28+20+%2B+59.464+%29+%2F+14+\"
\n" ); document.write( "\"+s+=+79.464+%2F+14+\"
\n" ); document.write( "\"+s+=+5.676+\"
\n" ); document.write( "The speed in still water is 5.676 mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( "(1) \"+10+=+%28+s+-+4+%29%2At+\"
\n" ); document.write( "(1) \"+10+=+%28+5.676+-+4+%29%2At+\"
\n" ); document.write( "(1) \"+10+=+1.676%2At+\"
\n" ); document.write( "(1) \"+t+=+5.967+\" hrs
\n" ); document.write( "-------------------
\n" ); document.write( "(2) \"+10+=+%28+s+%2B+4+%29%2A%28+7+-+5.967+%29+\"
\n" ); document.write( "(2) \"+10+=+%28+s+%2B+4+%29%2A1.033+\"
\n" ); document.write( "(2) \"+9.681+=+s+%2B+4+\"
\n" ); document.write( "(2) \"+s+=+5.681+\"
\n" ); document.write( "----------------
\n" ); document.write( "This is pretty close. Error could be
\n" ); document.write( "due to rounding off. I think the method
\n" ); document.write( "is correct anyway.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );