document.write( "Question 679613: At 7:00 am, Brooke leaves home to go on a business trip driving 35 mph. Fifteen minutes later, Bart discovers that Brooke forgot
\n" ); document.write( "her presentation materials. He drives 50 mph to catch up with her. What time will Bart catch Brooke?
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Algebra.Com's Answer #421984 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+15+\" min = \"+1%2F4+\" hr
\n" ); document.write( "Brooke has a head start of \"+d%5B1%5D+=+35%2A%28+1%2F4+%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+8.75+\"
\n" ); document.write( "Let \"+d+\" = the distance Bart drives to catch Brooke
\n" ); document.write( "Let \"+t+\" = the elapsed time from 7:15 until
\n" ); document.write( "Bart catches Brooke
\n" ); document.write( "--------------------
\n" ); document.write( "Brooke's equation:
\n" ); document.write( "(1) \"+d+-+8.75+=+35t+\"
\n" ); document.write( "Bart's equation:
\n" ); document.write( "(2) \"+d+=+50t+\"
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\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+50t+-+8.75+=+35t+\"
\n" ); document.write( "(1) \"+15t+=+8.75+\"
\n" ); document.write( "(1) \"+t+=+8.75+%2F+15+\"
\n" ); document.write( "(1) \"+t+=+.58333+\" hrs
\n" ); document.write( "(1) \"+t+=+.58333+%2A+60+\" min
\n" ); document.write( "(1) \"+t+=+35+\" min
\n" ); document.write( "Bart catches Brooke at 7:15 + 35 = 7:50 AM
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