document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679542>Question 679542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve the following;\r<BR>\n" );
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document.write( "The complement of an angle measures 10(degrees) less than one-fifth of its supplement. Find the measure of the angle.\r<BR>\n" );
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document.write( "I started out by writing: 90-x = 10 -1/5(90 - x)\r<BR>\n" );
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document.write( "I\"m not sure how to handle the fraction (one-fifth).  The answer is x=80. Everything I've tried did not work. Your help is appreciated. \r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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document.write( "Joshua </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421969 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle =x<BR>\n" );
document.write( "complement= (90-x)<BR>\n" );
document.write( "supplement = 180-x\r<BR>\n" );
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document.write( "(90-x)= 1/5(180-x)-10\r<BR>\n" );
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document.write( "multiply the equation by 5\r<BR>\n" );
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document.write( "5(90-x)= (180-x)-50\r<BR>\n" );
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document.write( "450-5x=180-x-50\r<BR>\n" );
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document.write( "5x-x= 450-180+50\r<BR>\n" );
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document.write( "4x=320<BR>\n" );
document.write( "/4<BR>\n" );
document.write( "x=80 deg\r<BR>\n" );
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document.write( " </SPAN>\n" );
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