document.write( "Question 61329: A cash register had 5 times as many quarters as nickels, two fewer dimes than nickels, and 30 pennies. All together, the cash register contains $8.50 in change. How many nickles are in the cash register? \n" ); document.write( "
Algebra.Com's Answer #42196 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
We'll let x=number of nickels in register
\n" ); document.write( "Then 5x=number of quarters
\n" ); document.write( "and (x-2)=number of dimes
\n" ); document.write( "and 30=number of pennies\r
\n" ); document.write( "\n" ); document.write( "Whatever monetary units we deal in (pennies, nickels, dollars, etc.), we have to be consistent. I choose to deal in pennies.\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amt of money in nickels (x)(5)plus the amt of money in dimes(x-2)(10)plus the amt of money in quarters (5x)(25) plus the pennies (30) has to equal 850. (Remember, we are dealing in pennies). Thus, our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "5x+10(x-2)+5x(25)+30=850 Simplifying, we get:
\n" ); document.write( "5x+10x-20+125x+30=850 further simplifying, we get:
\n" ); document.write( "140x=840\r
\n" ); document.write( "\n" ); document.write( "x=6 nickels
\n" ); document.write( "5x=(5)(6)=30 quarters
\n" ); document.write( "x-2=6-2=4 dimes
\n" ); document.write( "and, of course, 30 cents\r
\n" ); document.write( "\n" ); document.write( "Hope this helps ----ptaylor\r
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