document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679467>Question 679467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the shortest side of a 30-60-90 triangle is 20 cm, what are the lengths of the other two sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421953 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the shortest side of a 30-60-90 triangle is 20 cm, what are the lengths of the other two sides?<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "The sides are in a ratio of 1:2:sqrt(3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "If the shortest side is 20, the hypotenuse is 2*20 = 40,<BR>\n" );
document.write( "and the 2nd leg is 20*sqrt(3)<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );