document.write( "Question 679293: find the length and width of a rectangle whose perimeter is 34 feet and whose area is 60 square feet. \n" ); document.write( "
Algebra.Com's Answer #421908 by ReadingBoosters(3246)\"\" \"About 
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p = 34 = 2w+2l
\n" ); document.write( "a = 60 = wl; l = 60/w
\n" ); document.write( "...
\n" ); document.write( "2w + 2(60/w) = 34
\n" ); document.write( "2w + 120/w = 34
\n" ); document.write( "2w^2 + 120 = 34w
\n" ); document.write( "2w^2 - 34w + 120 = 0
\n" ); document.write( "(2w-10)(w-12)\r
\n" ); document.write( "\n" ); document.write( "w = 10/2 = 5
\n" ); document.write( "w = 12
\n" ); document.write( "...
\n" ); document.write( "lenth and width are 5ft and 12ft
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\n" ); document.write( "Check
\n" ); document.write( "5*12 = 60
\n" ); document.write( "2(5) + 2(12) = 10 + 24 = 34\r
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