document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=679076>Question 679076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this word problem: Dollah is three times as old as Kumar. In 12 years' time the sum of their age will be equal to 10 times Kumar's present age. Find their present aage. THANKS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421807 by </B><A HREF=/tutors/aboutme.mpl?userid=rm29924><B>rm29924(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rm29924><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rm29924><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X = Kumar's present age<BR>\n" );
document.write( "Dollah's present age is 3X\r<BR>\n" );
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document.write( "X+12 = Kumar's age in 12 years<BR>\n" );
document.write( "3X+12 = Dollah's age in 12 years\r<BR>\n" );
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document.write( "th sum of their ages in 12 years<BR>\n" );
document.write( "sum means add<BR>\n" );
document.write( "will equal 10X\r<BR>\n" );
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document.write( "Our equation is:<BR>\n" );
document.write( "X+12+3X+12=10X<BR>\n" );
document.write( "4X+24=10X<BR>\n" );
document.write( "subtract 4X from both sides<BR>\n" );
document.write( "24=6X<BR>\n" );
document.write( "divide 6 from both sides to get X by itself<BR>\n" );
document.write( "X=4\r<BR>\n" );
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document.write( "Kumar's present age is 4 years old.<BR>\n" );
document.write( "Dollah is 3X   3(4)=12   Dollah's present age is 12 years old.<BR>\n" );
document.write( " </SPAN>\n" );
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