document.write( "Question 61297: a. |x| <5\r
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document.write( "b. |x| = 5\r
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document.write( "c. |2x-3| <7\r
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document.write( "d. |3x+2| = 5 \n" );
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Algebra.Com's Answer #42178 by joyofmath(189)![]() ![]() ![]() You can put this solution on YOUR website! a. |x| <5\r \n" ); document.write( "\n" ); document.write( "b. |x| = 5\r \n" ); document.write( "\n" ); document.write( "c. |2x-3| <7\r \n" ); document.write( "\n" ); document.write( "d. |3x+2| = 5\r \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "a. -5 < x < 5\r \n" ); document.write( "\n" ); document.write( "b. x = -5 or x = 5\r \n" ); document.write( "\n" ); document.write( "c. -7 < 2x-3 < 7 \n" ); document.write( "Do the left side of the inequality: -7 < 2x-3, then -4 < 2x or -2 < x. \n" ); document.write( "Do the right side of the inequality: 2x-3 < 7, then 2x < 10 or x < 5.\r \n" ); document.write( "\n" ); document.write( "So, put the left and right sides together and you get \n" ); document.write( "\n" ); document.write( "d. 3x+2 = 5 or 3x+2 = -5 \n" ); document.write( "The first equality: 3x+2 = 5 then x=1. \n" ); document.write( "The second equality: 3x+2 = -5 then 3x = -7 or x = -7/3. \n" ); document.write( " |