document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678995>Question 678995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jet can fly 550mph in calm air. Traveling with the wind, the jet can fly 2400 miles in the same amount of time it takes to fly 2000 miles against the wind. Find the rate of the wind. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421750 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let rate of wind be x m/h\r<BR>\n" );
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document.write( "speed against wind 550-x m/h----------- 2000 miles<BR>\n" );
document.write( "speed with wind = 550+x m/h------------2400 miles\r<BR>\n" );
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document.write( "time = d/r\r<BR>\n" );
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document.write( "time against = time with\r<BR>\n" );
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document.write( "2000/(550-x)= 2400/(550+x)<BR>\n" );
document.write( "2000(550+x)=2400(550-x)<BR>\n" );
document.write( "1100000+2000x=1320000-2400x\r<BR>\n" );
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document.write( "2400x+2000x=1320000-1100000\r<BR>\n" );
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document.write( "4400x=220000<BR>\n" );
document.write( "x= 50 m/h </SPAN>\n" );
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