document.write( "Question 678935: find n such that the slope of the line containing (7,-12) and (n n+4) is parallel to 2x+y+8 \n" ); document.write( "
Algebra.Com's Answer #421702 by ReadingBoosters(3246)\"\" \"About 
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Start with 2x+y+8, is this 2x+y+8=0 or 2x+y=8 ???
\n" ); document.write( "y = -2x-8
\n" ); document.write( "Therefore, the slope is -2
\n" ); document.write( "...
\n" ); document.write( "A parallel line will have the SAME slope
\n" ); document.write( "...
\n" ); document.write( "Using the point(7,-12) and the determined slope apply point slope formula
\n" ); document.write( "y--12 = -2(x-7)
\n" ); document.write( "y+12 = -2(x-7)
\n" ); document.write( "y+12 = -2x+14
\n" ); document.write( "y = -2x + 14 - 12
\n" ); document.write( "y = -2x + 2
\n" ); document.write( "...
\n" ); document.write( "Applying the n variable point
\n" ); document.write( "n+4 = -2n + 2
\n" ); document.write( "solve for n
\n" ); document.write( "n + 2n = 2 - 4
\n" ); document.write( "3n = -2
\n" ); document.write( "n = -\"2%2F3\"
\n" ); document.write( "...
\n" ); document.write( "Alternatively, applying the slope formula
\n" ); document.write( "\"%28-12-%28n%2B4%29%29%2F%287-n%29+=+-2%2F1\"
\n" ); document.write( "\"%28-12-n-4%29%2F%287-n%29+=+-2%2F1\"
\n" ); document.write( "\"%28-16-n%29%2F%287-n%29+=+-2%2F1\"
\n" ); document.write( "cross multiply
\n" ); document.write( "(-16-n) = -2(7-n)
\n" ); document.write( "-16 - n = -14 + 2n
\n" ); document.write( "solve for n
\n" ); document.write( "-16 + 14 = 2n + n
\n" ); document.write( "-2 = 3n
\n" ); document.write( "n = -\"2%2F3\"
\n" ); document.write( ".....................
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