document.write( "Question 678974: y+1= square root of 5y-1 \n" ); document.write( "

Algebra.Com's Answer #421690 by ReadingBoosters(3246) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"y%2B1+=+sqrt%285y-1%29\"$
\n" ); document.write( "...
\n" ); document.write( " $\"%28y%2B1%29%5E2+=+sqrt%285y-1%29%5E2\"$
\n" ); document.write( "...
\n" ); document.write( " $\"y%5E2%2B2y+%2B+1+=+5y+-+1\"$
\n" ); document.write( "...
\n" ); document.write( " $\"y%5E2+%2B+2y+-+5y+%2B+1+%2B+1+=+0\"$
\n" ); document.write( "...
\n" ); document.write( " $\"y%5E2+-+3y+%2B+2+=+0\"$
\n" ); document.write( "...
\n" ); document.write( "(y-2)(y-1) = 0
\n" ); document.write( "y-1=0, so y = 1
\n" ); document.write( "y-2=0, so y = 2
\n" ); document.write( ".....................
\n" ); document.write( "Delighted to help; feel free to email if you have further questions.
\n" ); document.write( "HomeworkHelpers@readingboosters.com
\n" ); document.write( "-Reading Boosters
\n" ); document.write( "Website: www.MyHomeworkAnswers.com
\n" ); document.write( "Wanting for others what we want for ourselves.
\n" ); document.write( " \n" ); document.write( "

\n" );