document.write( "Question 678881: Please help me find the equation to help me solve the following word problem:\r
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document.write( "Mr. Fox and Mr. Ox are running to the other endof the football field. It takes Mr. Ox 2 seconds to run 10 yards ad Mr. Fox 5 second to run 10 yards. Mr. Fox had a 20 yard head start. How long does it take Mr. Ox to catch Mr. Fox? \n" );
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Algebra.Com's Answer #421689 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mr. Fox and Mr. Ox are running to the other end of the football field. \n" ); document.write( " It takes Mr. Ox 2 seconds to run 10 yards \n" ); document.write( " ad Mr. Fox 5 second to run 10 yards. \n" ); document.write( " Mr. Fox had a 20 yard head start. \n" ); document.write( " How long does it take Mr. Ox to catch Mr. Fox? \n" ); document.write( ": \n" ); document.write( "Find O's speed: 10/2 = 5 yds/sec \n" ); document.write( "Find F's speed: 10/5 = 2 yds/sec \n" ); document.write( ": \n" ); document.write( "Let t = time for O to catch F (in seconds) \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( ": \n" ); document.write( "O's dist = F's dist + 20 yds \n" ); document.write( "5t = 2t + 20 \n" ); document.write( "5t - 2t = 20 \n" ); document.write( "3t = 20 \n" ); document.write( "t = 20/3 sec, about 6.67 seconds \n" ); document.write( ": \n" ); document.write( "Check this, how many yards each ran \n" ); document.write( "6.67 * 5 = 33.3 yds; O's run \n" ); document.write( "6.67 * 2 = 13.3 yds: F's run \n" ); document.write( "------------------------ \n" ); document.write( "difference: 20 yds \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |