document.write( "Question 678815: Question:
\n" ); document.write( "Write an equation in slope-intercept form of the line satisfying the given conditions...
\n" ); document.write( "Perpendicular to the line y=2x+3; containing the point (-2,-4).\r
\n" ); document.write( "\n" ); document.write( "My answer was wrong, but here it is: y= -1/2x-4
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Algebra.Com's Answer #421633 by ReadingBoosters(3246)\"\" \"About 
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Using y=2x+3, the slope is \"2\"
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\n" ); document.write( "A perpendicular line will have the negative inverse (reciporcal) slope of \"-1%2F2\"
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\n" ); document.write( "Using the point (-2,-4) and the determined slope, plug into the point-slope formula.
\n" ); document.write( "y - -4 = \"-1%2F2\"(x--2)
\n" ); document.write( "y + 4 = \"-1%2F2\"(x+2)
\n" ); document.write( "y + 4 = \"%28-1%2F2%29x+-+%281%2F2%29%282%29\"
\n" ); document.write( "...
\n" ); document.write( "y = \"%28-1%2F2%29x+-+1-4\"
\n" ); document.write( "...
\n" ); document.write( "\"highlight_green%28y=%28-1%2F2%29x-5%29\"
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