document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678790>Question 678790</A>: <I><SPAN STYLE=\"word-break: break-all;\">  1) If all permutations of the letters of the words AGAIN are arranged as in dictionary,then what is 49th word? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421618 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you list out all the permutations of AGAIN, there are 120 of them.\r<BR>\n" );
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document.write( "However, there's a letter that repeats itself twice (A), so cut that figure in half to get 60.\r<BR>\n" );
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document.write( "So there are 60 ways to rearrange the letters of AGAIN\r<BR>\n" );
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document.write( "That's a lot. Especially if you have to sort them all correctly.\r<BR>\n" );
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document.write( "However, doing so will give the 49th \"word\" <font color=\"red\">NAAGI</font>. </SPAN>\n" );
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