document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678370>Question 678370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 210m.  If the length of this rectangle is three-fourths of its width, its dimensions are?   I attempted solving this by using the equation  P= 2L + 2W; and attempting to solve for the length, etc.  I'm still stumped with the 3/4.<BR>\n" );
document.write( "Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421457 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3/4W<BR>\n" );
document.write( "2L+2W=210<BR>\n" );
document.write( "2(3W/4)+2W=210<BR>\n" );
document.write( "6W/4+2W=210<BR>\n" );
document.write( "(6W+4*2M)/4=210<BR>\n" );
document.write( "(6W+8W)/4=210<BR>\n" );
document.write( "14W/4=210<BR>\n" );
document.write( "14W=210*4<BR>\n" );
document.write( "14W=840<BR>\n" );
document.write( "W=840/14<BR>\n" );
document.write( "W=60 ANS.<BR>\n" );
document.write( "L=(3/4)60<BR>\n" );
document.write( "L=45 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*60+2*45=210<BR>\n" );
document.write( "120+90=210<BR>\n" );
document.write( "210=210<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );