document.write( "Question 678479: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length.\r
\n" ); document.write( "\n" ); document.write( "This real-world problem can be solved using a linear equation.\r
\n" ); document.write( "\n" ); document.write( "First express the length L of the rectangle in terms of the width W. We are given that the length is 3 feet less than twice the width.
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Algebra.Com's Answer #421424 by rm29924(97)\"\" \"About 
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perimeter of a rectangle=
\n" ); document.write( "perimeter=2(length)+2(width)
\n" ); document.write( "perimeter=474 feet
\n" ); document.write( "let W=width
\n" ); document.write( "the length=2W-3
\n" ); document.write( "W+2W-3=474
\n" ); document.write( "3w-3=474
\n" ); document.write( "3w=477
\n" ); document.write( "w=159\r
\n" ); document.write( "\n" ); document.write( "length is 2W-3
\n" ); document.write( "2(159)-3
\n" ); document.write( "318-3
\n" ); document.write( "315\r
\n" ); document.write( "\n" ); document.write( "the width is 159 ft and the length is 315 ft
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