document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678462>Question 678462</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A container has 6 litres f a 40% alcohol solution in it. How much pure alcohol should be added to raise it to be a 60% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421419 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A container has 6 litres f a 40% alcohol solution in it. How much pure alcohol should be added to raise it to be a 60% solution?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = amount (liters) of pure alcohol added<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x + .40(6) = .60(x+6)<BR>\n" );
document.write( "x + 2.4 = .60x+3.6<BR>\n" );
document.write( ".40x + 2.4 = 3.6<BR>\n" );
document.write( ".40x = 1.2<BR>\n" );
document.write( "x = 3 litres </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );