document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61250>Question 61250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5/2 x + 3 =1/2 x +15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42139 by </B><A HREF=/tutors/aboutme.mpl?userid=DJ_Sammie><B>DJ_Sammie(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DJ_Sammie><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://myspace-054.vo.llnwd.net/00469/45/02/469102054_l.jpg valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/2x+3=1/2x+15\r<BR>\n" );
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document.write( "you have to get the variable on one side\r<BR>\n" );
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document.write( "so subtract 1/2x from both sides\r<BR>\n" );
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document.write( "5/2x+3-1/2x=1/2x+15-1/2x<BR>\n" );
document.write( "4/2x+3=15\r<BR>\n" );
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document.write( "then simplify\r<BR>\n" );
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document.write( "2x+3=15\r<BR>\n" );
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document.write( "subtract 3 from both sides\r<BR>\n" );
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document.write( "2x+3-3=15-3<BR>\n" );
document.write( "2x=12\r<BR>\n" );
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document.write( "then divide by 2\r<BR>\n" );
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document.write( "2x/2=12/2<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "x equals 6 </SPAN>\n" );
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