document.write( "Question 678409: 2 years before father was twice as old as his son and hence after 2 years thrice the age of father equals to 5 times the age of son.find their present ages? \n" ); document.write( "
Algebra.Com's Answer #421362 by ankor@dixie-net.com(22740)\"\" \"About 
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2 years before father was twice as old as his son and hence after 2 years thrice the age of father equals to 5 times the age of son.find their present ages?
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\n" ); document.write( "Let f = father's present age
\n" ); document.write( "Let s = son's present age
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\" 2 years before father was twice as old as his son\"
\n" ); document.write( "f - 2 = 2(s - 2)
\n" ); document.write( "f - 2 = 2s - 4
\n" ); document.write( "f = 2s - 4 + 2
\n" ); document.write( "f = 2s - 2
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\n" ); document.write( "\"and hence after 2 years thrice the age of father equals to 5 times the age of son.\"
\n" ); document.write( "3(f+2) = 5(s+2)
\n" ); document.write( "3f + 6 = 5s + 10
\n" ); document.write( "3f = 5s + 10 - 6
\n" ); document.write( "3f = 5s + 4
\n" ); document.write( "Replace f with (2s-2)
\n" ); document.write( "3(2s-2) = 5s + 4
\n" ); document.write( "6s - 6 = 5s + 4
\n" ); document.write( "6s - 5s = 4 + 6
\n" ); document.write( "s = 10 is the son's present age
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\n" ); document.write( "I'll let you find f, check the solutions in the given statements\r
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