document.write( "Question 678353: A cylindrical tank with a diameter of 20 feet is filled with oil to a depth of 40 feet. The oil begins draining at a constant rate of 2 cubic feet per second. [Hint: depth and volume are not the same]\r
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document.write( "a) Write the volume of the oil remaining the tank t seconds later as a function of t.\r
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document.write( "b) Write the depth of the oil remaining in the tank t seconds later as a function of t. \n" );
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Algebra.Com's Answer #421355 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A cylindrical tank with a diameter of 20 feet is filled with oil to a depth of 40 feet. \n" ); document.write( ": \n" ); document.write( "Find the original volume of the oil; (radius = 10 ft) \n" ); document.write( "V = \n" ); document.write( "V = 12566.37 cu/ft of oil \n" ); document.write( ": \n" ); document.write( "The oil begins draining at a constant rate of 2 cubic feet per second. [Hint: depth and volume are not the same] \n" ); document.write( "a) Write the volume of the oil remaining the tank t seconds later as a function of t. \n" ); document.write( "V = 12566.37 - 2t \n" ); document.write( ": \n" ); document.write( "b) Write the depth of the oil remaining in the tank t seconds later as a function of t. \n" ); document.write( "Find the depth (x) of 2 cu ft in this tank, let \n" ); document.write( " \n" ); document.write( "x = \n" ); document.write( "x = .0063662 ft per second at a 2 cu/ft per second rate \n" ); document.write( "d = 40 - .0063662t \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check this by finding how long it will take to empty the tank \n" ); document.write( "12566.37/2 = 6283.2 seconds \n" ); document.write( "Find the depth of oil drained in this time \n" ); document.write( "6283.2 * .0063662 = 40.00 ft \n" ); document.write( " |