document.write( "Question 678403: Solve by completing the solve\r
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Algebra.Com's Answer #421345 by santukeerti(5)\"\" \"About 
You can put this solution on YOUR website!
6z^2=z+2
\n" ); document.write( "6z^2-z-2=0
\n" ); document.write( "\"z+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%2A6%2A%28-2%29+%29%29%2F%282%2A6%29+\"
\n" ); document.write( "z=1+- sqrt( 1+48 )/12
\n" ); document.write( "z=1 +- sqrt (49)/12
\n" ); document.write( "z= 1 +- 7/12
\n" ); document.write( "z= (12 +- 7)/12
\n" ); document.write( "z= (19/12), (5/12)
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