document.write( "Question 677850: in the sketch given i have a vertex of (0 ; -4) and one x intercept of (2 ; 0) how do i determine the parabola equation in standard form \n" ); document.write( "

Algebra.Com's Answer #421343 by lwsshak3(11628) $\"\"$ $\"About$

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in the sketch given i have a vertex of (0 ; -4) and one x intercept of (2 ; 0) how do i determine the parabola equation in standard form
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\n" ); document.write( "Standard form of equation for parabolas: y=A(x-h)^2+k, (h,k)=coordinates of the vertex
\n" ); document.write( "given equation: y=A(x-0)^2-4
\n" ); document.write( "solve for A using coordinates of given x-intercept (2,0)
\n" ); document.write( "0=A(2-0)^2-4
\n" ); document.write( "4A=4
\n" ); document.write( "A=1
\n" ); document.write( "equation: y=x^2-4
\n" ); document.write( "see graph below:
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-4%29+\"$ \n" ); document.write( "

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