document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678384>Question 678384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A working student has to deliver a package to a client. Before he can reach the client's office, he has to travel 3 km due to east, then 4 km due to south, and then 6 km due to west. How far is their office from the client's office? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421331 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you plot this on a coordinate plane starting at (0,0) you see it ends up at the point (-3,-4).  Use the distance formula between the two points.  The distance formula is the squareroot of the difference between the x's squared plus the distance between the y's squared.<P><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%280%2B+-3%29%5E2+%2B+%280+%2B+-4%29%5E2%29+=+sqrt%289%2B16%29+=+sqrt%2825%29+=+5 ALIGN=MIDDLE  ALT=\"sqrt%28%280%2B+-3%29%5E2+%2B+%280+%2B+-4%29%5E2%29+=+sqrt%289%2B16%29+=+sqrt%2825%29+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The distance is 5 miles.<BR>\n" );
document.write( "<P>Hope the solution helped.  Sometimes you need more than a solution.  Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );