document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=678348>Question 678348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421300 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length.<BR>\n" );
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document.write( "Let the width be \"w\":<BR>\n" );
document.write( "Then the length is \"2w-3\"<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Perimeter = 2(width + length)<BR>\n" );
document.write( "474 = 2(w + 2w-3)<BR>\n" );
document.write( "237 = 3w-3<BR>\n" );
document.write( "3w = 240<BR>\n" );
document.write( "w = 80 feet (width)<BR>\n" );
document.write( "2w-3 = 157 feet (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
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