document.write( "Question 678198: Hello, I need help with a quadratic equation. I get stuck at the part where I need to simplify inside the radical. The problem I am currently on is: $\"+2x%5E2-7x-5=0+\"$ \r
\n" ); document.write( "\n" ); document.write( "Thank you for your help.\r
\n" ); document.write( "\n" ); document.write( "P.S. I need to leave the answer in radical form. \n" ); document.write( "

Algebra.Com's Answer #421209 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+2x%5E2-7x-5=0+\"$
\n" ); document.write( "to solve, you can apply the \"quadratic formula\":
\n" ); document.write( "[-b +- sqrt(b^2 - 4ac)]/(2a)
\n" ); document.write( "[-(-7) +- sqrt((-7)^2 - 4(2)(-5))]/(2*2)
\n" ); document.write( "[7 +- sqrt(49 - (-40))]/(4)
\n" ); document.write( "[7 +- sqrt(49+40)]/4
\n" ); document.write( "[7 +- sqrt(89)]/4
\n" ); document.write( "but, since 89 is \"prime\" you cannot simplify underneath the radical.
\n" ); document.write( "giving you the answer of:
\n" ); document.write( "7/4 +- sqrt(89)/4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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