document.write( "Question 61194: Please help. Write the equation of a line, in standard form with the integer coefficiants, that passes through the points (6,7) and (-2,15) PLEASE SHOW ME THE WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! and how to solve.
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Algebra.Com's Answer #42120 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! FIRST WE FIND THE SLOPE USING THE TWO POINTAS GIVEN (Y2-Y1)/(X2-X1) \n" ); document.write( "(15-7)/(-2-6) \n" ); document.write( "8/-8=-1 FOR THE SLOPE \n" ); document.write( "NOW REPLACING Y+X IN THE LINE FORMULA (Y=mX+b) WITH -1 FOR (m) & WITH ONE SET OF THE COORDINATES WE GET \n" ); document.write( "6=-7+b AND SOLVE FOR b (THE Y INTERCEPT) \n" ); document.write( "6+7=b \n" ); document.write( "b=13 \n" ); document.write( "THIS GIVE US THE EQUATION Y=-X+13 FOR THIS LINE WITH A SLOPE OF (-1)& A Y INTERCEPTOF (13) \n" ); document.write( "----------------------------------------------------------------------------- \n" ); document.write( "WHAT YOU MAY NEED IS TO GRAPH THESE TYPEOFPROBLEMS USING GRAPH PAPER. \n" ); document.write( "IF YOU DON'T HAVE ANY JUST GO TO ANY STAPLES OR STORE THAT SELLS PAPER PRODUCTS AND GET A PAD OF GRAPH PAPER. DRAW THE X (VERTICLE LINE) & Y (HORIZONTAL) LINE IN THE MIDDLE OF THE PAGE. THEN LABEL THE MANY UNITS TO THE RIGHT OF THE LINE INTERSECTION PLUS X (+X) VALUES, UNITS TO THE LEFT AS MINUS X (-X) VALUES, THEN LABEL THE UNITS ABOVE THE INTERSECTION PLUS Y (+Y)VALUES AND THE UNITS BELOW THE INTERSECTION MINUS Y (-Y)VALUES. \n" ); document.write( "IF YOU NEED MORE HELP GET A GEOMETRY TEXT BOOK FROM THE LOCAL LIBRARY. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |