document.write( "Question 677975: Find a polynomial f(x) of degree 3 with real coefficients and the following zeros.\r
\n" ); document.write( "\n" ); document.write( "-4, -1, i\r
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Algebra.Com's Answer #421124 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
I think you may have meant one of two things. Either the degree is supposed to be 4, or -1 was supposed to be -i. As you may know, imaginary roots come in conjugate pairs, so with i, we are guaranteed -i to be a root as well. So if -4,-1,i are roots then -i is a root as well, which gives us degree 4.\r
\n" ); document.write( "\n" ); document.write( "So I'll solve it both ways.\r
\n" ); document.write( "\n" ); document.write( "If you meant -4,-1,i with degree 4, that's\r
\n" ); document.write( "\n" ); document.write( "(x+4)(x+1)(x-i)(x+i)\r
\n" ); document.write( "\n" ); document.write( "[x^2+5x+4][x^2+1] = x^4 + 5x^3 + 5x^2 + 5x + 4\r
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\n" ); document.write( "\n" ); document.write( "If you meant -4,-i,i then that's\r
\n" ); document.write( "\n" ); document.write( "(x+4)(x-i)(x+i)\r
\n" ); document.write( "\n" ); document.write( "(x+4)(x^2+1) = x^3 + 4x^2+ x + 4
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