document.write( "Question 677976: Write a Quadratic Equation given these solutions:
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document.write( "x = 1/3 and x = 1/4
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document.write( "how do I solve that?? and also for
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document.write( "x= -1/2 and x = -2/3
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Algebra.Com's Answer #421121 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! x=1/3\r \n" ); document.write( "\n" ); document.write( "Multiply 3 on both sides:\r \n" ); document.write( "\n" ); document.write( "3x = 1\r \n" ); document.write( "\n" ); document.write( "subtract 1.\r \n" ); document.write( "\n" ); document.write( "3x-1\r \n" ); document.write( "\n" ); document.write( "x = 1/4\r \n" ); document.write( "\n" ); document.write( "By the same method:\r \n" ); document.write( "\n" ); document.write( "4x-1\r \n" ); document.write( "\n" ); document.write( "So a quadratic function with roots 1/3 and 1/4 is (3x-1)(4x-1)\r \n" ); document.write( "\n" ); document.write( "FOIL to get:\r \n" ); document.write( "\n" ); document.write( "12x^2-4x-3x+1\r \n" ); document.write( "\n" ); document.write( "which is 12x^2-7x+1\r \n" ); document.write( "\n" ); document.write( "2)\r \n" ); document.write( "\n" ); document.write( "x=-1/2 ---> (2x+1)\r \n" ); document.write( "\n" ); document.write( "x=-2/3 ----> (3x+2)\r \n" ); document.write( "\n" ); document.write( "FOIL that out to get 6x^2+7x+2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |