document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=677939>Question 677939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three friends were born in consecutive years. The sum of their birth year is 5982. Find the year in which each person was born. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #421117 by </B><A HREF=/tutors/aboutme.mpl?userid=madman1101><B>madman1101(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=madman1101><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=421117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b+c=5982<BR>\n" );
document.write( "find the average of the 3 friends<BR>\n" );
document.write( "5982/3=1994<BR>\n" );
document.write( "add and subtract 1 to find an average<BR>\n" );
document.write( "1994+1=1995<BR>\n" );
document.write( "1994-1=1993<BR>\n" );
document.write( "add all years together to check<BR>\n" );
document.write( "1993+1994+1995=5982 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );